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Message: 975 - Contents - Hide Contents

Date: Wed, 05 Sep 2001 23:03:45

Subject: Re: Tenney's harmonic distance

From: genewardsmith@j...

--- In tuning-math@y..., "Paul Erlich" <paul@s...> wrote:

> You better believe it! So, any comments on the questions I asked?
I'll look at it again, but I have some questions also: (1) Can you define harmonic entropy in terms of your taxicab metric, or if not in any terms you like? (2) Do you know how to retune a midi file in such a way that the pitches are set to anything you choose?
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Message: 976 - Contents - Hide Contents

Date: Wed, 05 Sep 2001 23:22:00

Subject: Re: Question for Gene

From: genewardsmith@j...

--- In tuning-math@y..., "Paul Erlich" <paul@s...> wrote:

> In particular, I'm assuming a city-block or taxicab metric. Is Kees > observing that in his final lattice? It looks like he isn't.
Kees is talking about circles and transforming as if in a Euclidean space, so you aren't on the same wavelength.
> What else can you say?
I'm not sure what your triangular lattice metric is. A taxicab needs two lines to run along; you can make these 120 degrees to each other but you can't get an array of equilateral triangles out of it. By "lattice", mathematicians usually mean one of two things. The first has to do with partial orderings and need not concern us, the second defines a lattice as a discrete subgroup of R^n whose quotient group is compact. I'm not always sure what people mean when they say lattice in this neighborhood.
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Message: 977 - Contents - Hide Contents

Date: Thu, 06 Sep 2001 03:26:37

Subject: about hypothesis and theorem

From: Pierre Lamothe

Hi Paul and tuning-math members

I was surprised to find intense (and abstract) activity on the List after
my vacation. It takes a while before I have leisure to read all that. I
regret to have not the possibility to participate. However I would like
simply to ask a question permitting to see it misses probably a condition.

Let u and v be the vectors 25/24 and 27/20 in the lattice <2 3 5> Z^3 whose
generic element is (2^x)(3^y)(5^z). The vectors u and v determine (with the
octave) the "pathologic" periodicity block <1 9/8 5/4 3/2 15/8> supposed
valid (in the theorem) since it corresponds to the homomorphism

   H(x,y,z) = 5x + 8y + 14z

Could you show how the hypothesis, the definitions, the conditions of
validity and the theorem would be applied in this case? Could you exhibit a
generator and a scale?

Pierre


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Message: 978 - Contents - Hide Contents

Date: Thu, 06 Sep 2001 07:39:23

Subject: Re: Theorem Paul

From: genewardsmith@j...

--- In tuning-math@y..., "Paul Erlich" <paul@s...> wrote:

> Now do you have a quick way of determining the generator of the > linear temperament, given n-1 commatic unison vectors?
Let's see if this helps: Recall that a notation for the note group N_p was a k-tuple of vals [u_1, ..., u_k], where k = pi(p) is the number of primes up to p, and where the kxk square matrix we get by writing the vals as column vectors is unimodular, meaning it has determinant +-1. We may call this the *val matrix* for the notation; corresponding to it is a *basis matrix* which is the matrix inverse of the val matrix. The rows of the basis matrix are the basis notes of the notation, and it may also be written as a k-tuple of rational numbers (q_1, ..., q_k) where if q_i = [e_1, e_2, ..., e_k] we also write it multiplicitively as the rational number q_i= 2^e_1 * 3^e_2 ... p^e_k. We then have for any prime r <= p r = q_1^u_1(r) * q_2^u_2(r) * ... q_k^u_k(r), so that anything which can be written as the product of the first k primes can also be written as the product of q_1, ..., q_k; that is, both are a basis for the note group N_p. I just downloaded Graham's midiconv program, and he is doing this sort of thing in his tun files. For instance, in 12from31.tun we find the matrix [-3 -1 2] [ 7 0 -3] [-4 4 -1] which is a basis matrix (since it is unimodular.) Inverting it we get the val matrix [12 7 3] [19 11 5] [28 16 7], which is the notation [h_12, h_7, h_3]. If you look at Graham's file you will see he is using this notation. Every note in N_5 can be expressed in terms of this notation as q = (25/24)^h_12(q) * (128/125)^h_7(q) * (81/80)^h_3(q) just as it can also be written q = 2^v_2(q) * 3^v_3(q) * 5^v_5(q), where v_2, v_3 and v_5 are the 2-adic, 3-adic and 5-adic valuations of number theory. Suppose now we want to temper out 81/80, so that we will write the approximation to q, ~q, as ~q = a^h_12(q) * b^h_7(q). Finding a basis for this temperament means the same as tuning the above basis, which we may do in various ways, e.g., least squares. If we like we may assume ~2 = 2, in which case we really need to specify only one value, since the other than be found from 2 = a^h_12(2) * b^h_7(2) = a^12 * b^7. To take another example, consider the basis matrix defined by the 5-tuple (176/175, 385/384, 8019/8000, 441/440, 540/539), which in matrix form is [ 4 0 -2 -1 1] [-7 -1 1 1 1] [-6 6 -3 0 1] [-3 2 -1 2 -1] [ 2 3 1 -2 -1]. The inverse of this matrix is [72 58 -31 53 46] [114 92 -49 84 73] [167 135 -72 123 107] [202 163 -87 149 129] [249 201 -107 183 159], which is the notation [h_72, h_58, -h_31, h_53, h_46]. If we remove any one element from the basis 5-tuple, and take octave equivalence in its place, we get a JI block whose number of notes is abs(h(2)) for the val corresponding to the basis element we removed. For instance, by taking out 540/539, which is in the kernel of all the vals but h_46, which has instead h_46(540/539)=1, we get a block of 46 notes. We may temper this in various ways by removing other val/basis pairs, getting equal, linear etc. temperaments. Thus for instance by tuning ~q = a^h_72(q) (for instance, in the usual way!) we get the 46 block expressed in the 72-et. If we tune ~q = a^h_72(q) * b^h_53(q), we get a linear temperament, and so forth. We also have for example that ker(h_72) is generated by all the basis vectors except 176/175, where h_72(176/175)=1. Just as each val is associated to the group it generates (of rank one) and hence to the dual group, i.e. the kernel, of corank one (in this case, that would be rank four), every basis note q_i generates a rank one group, whose dual group null(q_i) is of corank one (in this case four again.) While null(q_i) is of corank one and has an infinity of elements, if we list only valid vals of the form u_n for integers n we get a finite list, which is an interesting thing to consider for any comma-like interval. For instance, 128/125 is associated in this way to multiples of 3 through 42, excluding h_6 which is invalid. In the same way, 25/24 is associated to 3,4,7,10,13 and 17; and 81/80 to 5,7,12,19,26,31,43,45,50,55,67,69,74,81,88,98,105 and 117. If we place some limit based on a measure of goodness when we do this we of course can get an even smaller list.
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Message: 979 - Contents - Hide Contents

Date: Thu, 06 Sep 2001 08:20:11

Subject: Re: about hypothesis and theorem

From: genewardsmith@j...

--- In tuning-math@y..., Pierre Lamothe <plamothe@a...> wrote:

> Could you show how the hypothesis, the definitions, the conditions of > validity and the theorem would be applied in this case? Could you exhibit a > generator and a scale?
We find that h_4 has the property h_4(25/24)=0 and h_4(27/20)=1. We then look at vals of the form t*h_5 + h_4, and when t=1 we get [ 9] g = [13] [20]. Note that this is *not* h_9, which has coordinate values 9, 14 and 21. However, 7/5 is a semiconvergent to 13/9, 11/5 is a semiconvergent to 20/9 and for that matter 1/5 is a semiconvergent to 2/9. We get a scale of pattern 22221, 5 steps in a 9-et. It may not do a very good job of representing your "pathological" block, but then 27/20 is not much of a comma. If you want to exclude this kind of thing we need to change the statement of the theorem, but then we must ask what, exactly, people want to prove.
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